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10n^2-7n-6=0
a = 10; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·10·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*10}=\frac{-10}{20} =-1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*10}=\frac{24}{20} =1+1/5 $
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